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8
Nonlinear E lasticity
8.1
Molecular Approach to Rubber Elasticity
Many of today’s challenging design problems involve materials such as
. Rubber materials
might be most easily characterized by the stretching and relaxing of a rubber
band. The
butadiene rubber
(BR),
natural rubber
(NR), or
elastomers
of rubber, the ability to recover intial dimensions after
large strain, was not possible with natural latex until Charles Goodyear
discovered vulcanization in 1939. Vulcanization is a chemical reaction known
as cross-linking which turned liquid latex into a non-meltable solid
(
resilience
). Cross-linked rubber would also allow considerable stretching
with low damping; strong and stiff at full extension, it would then retract
rapidly (rebound). One of the first applications was rubber-impregnated
cloth, which was used to make the sailor’s “mackintosh.” Tires continue to
be the largest single product of rubber although there are many, many other
applications. These applications exhibit some or all of rubber’s four charac-
teristics, viz. damping in motor mounts, rebound/resilience in golf ball cores,
or simple stretching in a glove or bladder. While thermoset rubber remains
dominant in rubber production, processing difficulties have led to the devel-
opment and application of
thermoset
(TPEs). These materials
are easier to process and are directly recyclable. While TPEs are not as rubber-
like as the thermosets, they have found wide application in automotive fascia
and as energy-absorbing materials.
There are several reasons why designing with plastic and rubber materials
is more difficult than with metals. For starters, the stress-strain response,
that is, the constitutive response, is quite different. Figure 8.1A shows the
stress-strain curves for a mild steel specimen along with the response of a
natural rubber used in an engine mount. Note that the rubber specimen
strain achieves a much higher stretch value than the steel. The dashed ver-
tical line in Figure 8.1B represents the strain value of the mild steel at failure.
This value is much less than the 200% strain the rubber underwent without
failing. In fact, many rubber and elastomer materials can obtain 300 to 500%
thermoplastic elastomers
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FIGURE 8.1A
Nominal stress-stretch curve for mild steel.
FIGURE 8.1B
Nominal stress-stretch curve for natural rubber. Note the large stretch compared to the mild
steel curve.
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strain. Highly cross-linked and filled rubbers can result in materials not
intended for such large strains. Two-piece golf ball cores are much stiffer
than a rubber band, for instance. Each of these products is designed for
different strain regimes. A golf ball’s maximum strain would be on the order
of 40 to 50%. Its highly crosslined constitution is made for resilience, not for
large strain. The rubber stress-strain curve exhibits nonlinear behavior from
the very beginning of its deformation, whereas steel has a linear regime
below the yield stress.
The reason rubber materials exhibit drastically different behavior than
metals results from their sub-microscopic characteristics. Metals are crystal-
line lattices of atoms all being, more or less, well ordered: in contrast, rubber
material molecules are made up of carbon atoms bonded into a long chain
resembling a tangled collection of yarn scraps. Since the carbon-carbon (C-
C) bond can rotate, it is possible for these entangled long chain polymers to
rearrange themselves into an infinite number of different conformations.
While the random coil can be treated as a spring, true resilience requires a
cross-link to stop viscous flow. In a thermoset rubber, a chemical bond, often
with sulfur, affords the tie while physical entanglements effect the same
function in a TPE material. The degree of cross-linking is used to control the
rubber’s stiffness.
In the context of this book’s coverage of continuum mechanics, material
make-up on the micro-scale is inconsistent with the continuum assumption
discussed in Chapter One. However, a rubber elasticity model can be derived
from the molecular level which somewhat represents material behavior at
the macroscopic level. In this chapter, rubber elasticity will be developed
from a first-principle basis. Following that, the traditional continuum
approach is developed by assuming a form of the strain energy density and
using restrictions on the constitutive response imposed by the second law
of thermodynamics to obtain stress-stretch response.
One of the major differences between a crystalline metal and an amorphous
polymer is that the polymer chains have the freedom to rearrange them-
selves. The term conformation is used to describe the different spatial ori-
entations of the chain. Physically, the ease at which different conformations
are achieved results from the bonding between carbon atoms. As the carbon
atoms join to form the polymer chain, the bonding angle is 109.5°, but there
is also a rotational degree of freedom around the bond axis. For most macro-
molecules, the number of carbon atoms can range from 1,000 to 100,000.
With each bond having a certain degree of freedom to orient itself, the
number of conformations becomes quite large. Because of this substantial
amount, the use of statistical thermodynamics may be used to arrive at
rubber elasticity equations from first principles. In addition to the large
number of conformations for a single chain, there is another reason the
statistical approach is appropriate: the actual polymer has a large number
of different individual chains making up the bulk of the material. For
FIGURE 8.2
A schematic comparison of molecular conformations as the distance between molecule’s ends
varies. Dashed lines indicated other possible conformations.
instance, a cubic meter of an amorphous polymer having 10,000 carbon
atoms per molecule would have on the order of 10
molecules (McCrum
et al., 1997). Clearly, the sample is large enough to justify a statistical
approach.
At this point, consider one particular molecule, or polymer chain, and its
conformations. The number of different conformations the chain can obtain
depends on the distance separating the chain’s ends. If a molecule is formed
of
24
.
Separating the molecule’s ends, the length L would mean there is only one
possible conformation keeping the chain intact. As the molecule’s ends get
closer together, there are more possible conformations that can be obtained.
Thus, a Gaussian distribution of conformations as a function of the distance
between chain ends is appropriate. Figure 8.2 demonstrates how more con-
formations are possible as the distance between the molecule’s ends is
reduced.
Molecule end-to-end distance,
n
segments each having length
, the total length would be
L
=
n
l
l
, is found by adding up all the segment
lengths, as is shown in Figure 8.3 . Adding the segment lengths algebra-
ically gives distance
r
l
from end-to-end, but it does not give an indication of
the length of the chain. If the ends are relatively close and the molecule is
long there will be the possibility of many conformations. Forming the mag-
nitude squared of the end-to-end vector,
r
r
, in terms of the vector addition of
individual segments
2
r
=⋅= + + +
rr
llLl
llLl
+++
(8.1-1)
~~
~
~~
~
1
2
n
1
2
n
where
segment of the molecule chain. Mul-
tiplying out the right-hand side of Eq 8.1-1 leads to
is the vector defining the i
~ i
th
2
2
rn
= + ⋅ +⋅ + + ⋅
l
l l
l l
Ll
l
(8.1-2)
~~
~~
~
n
1
~
12
13
n
This would be the square of the end-to-end vectors for one molecule of the
polymer. In a representative volume of the material there would be many
chains from which we may form the mean square end-to-end distance
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FIGURE 8.3
A freely connected chain with end-to-end vector
r
.
N
1
=
l
2
2
r
n
+ ⋅ +⋅ + + ⋅
l l
l l
Ll
l
(8.1-3)
N
~~
~~
~
n
1
~
12
13
n
1
The bracketed term in Eq 8.1-3 is argued to be zero from the following logic.
Since a large number of molecules is taken in the sample, it is reasonable
that for every individual product there will be another segment pair
product which will equal its negative. The canceling segment pair does not
necessarily have to come from the same molecule. Thus, the bracketed term
in Eq 8.1-3 is deemed to sum to zero, leaving a simple expression for the
mean end-to-end distance
l ~ 12
2
2
r
= l
n
(8.1-4)
The mean end-to-end distance indicates how many segments, or carbon
atoms, are in a specific chain. To address the issue of how the end-to-end
distances are distributed throughout the polymer, a Gaussian distribution is
assumed. Pick the coordinate’s origin to be at one end of a representative
chain. Figure 8.3 shows this for a single chain, with the other end of the chain
in an infinitesimal volume
dV
located by the vector
r
. The probability of the
chain’s end lying in the volume
dV
is given by
2
r
ρ
e
() =
Prdr
dr
(8.1-5)
( )
3
πρ
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