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Eddy Current Losses in Transformer Windings and Circuit Wiring
Eddy Current Losses in Transformer
Windings and Circuit Wiring
Lloyd H. Dixon, Jr.
Introduction
As switching power supply operating fre-
quencies increase, eddy current losses and
parasitic inductances can greatly impair circuit
performance. These high frequency effects are
caused by the magnetic field resulting from
current flow in transformer windings and circuit
wiring.
This paper is intended to provide insight into
these phenomena so that improved high fre-
quency. performance can be achieved. Among
other things, it explains (I) why eddy current
losses increase so dramatically with more wind-
ing layers, (2) why parallelling thin strips does-
n't work, (3) how passive conductors (Faraday
shields and C.T .windings) have high losses,
and (4) why increasing conductor surface area
will actually worsen losses and parasitic induc-
tance if the configuration is not correct.
energy is stored in air gaps, insulation between
conductors, and within the conductors, where
relative permeability JLr is essentially 1.0 and
constant. The energy density then becomes:
w = \BH = \'tJ.(j/I2 J/m3
where ILOis the absolute permeability of free
space ( =47r .10"7 in S.I. units). Total energy W
(Joules) is obtained by integrating the energy
density over the entire volume, v, of the field:
W = \ILO f H2dv Joules
Within typical transformers and inductors, the
magnetic energy is almost always confined to
regions where the field intensity H is relatively
constant and quite predictable. This often oc-
curs in circuit wiring, as well. In these cases:
W = \ILO H2A. e Joules (2)
and from (1), He = NI. Substituting for H:
W = \ILO ~fA/e
Basic Principles
The following principles are used in the
development of this topic and are presented
here as a review of basic magnetics.
1. Ampere's Law: The total magneto-motive
force along any closed path is equal to the total
current enclosed by that path:
F = iHde = I, = NI Amps
Joules
(3)
(1)
whereA is the cross-section area (m1 of the
region normal to the flux, and e is the length
of the region in meters (and the effective
length of the field).
4. Circuit inductance: Inductance is a meas-
ure of an electrical circuit's ability to store
magnetic energy. Equating the energy stored in
the field from (3) with the same energy in
circuit terms:
W = \Lf = \ILO N2fA/e
L = ILON2A/e
where F is the total magneto-motive force
(in Amperes) along a path of length e (m), H
is field intensity (Aim), and I, is the total
current through all turns enclosed by the path.
2. Conservation or energy: At any moment
of time, the current within the conductors and
the magnetic field are distributed so as to
minimize the energy taken from the source.
3. Energy content or the field: The magnetic
field is energy. The energy density at any point
in the field is:
w = f HdB Jouleslm3
(4)
Skin Effect
Figure 1 shows the magnetic field (flux lines)
in and around a conductor carrying dc or low
frequency current I. The field is radially sym-
metrical, as shown, only if the return current
with its associated field is at a great distance.
At low frequency, the energy in the magnetic
field is trivial compared to the energy loss in
the resistance of the wire. Hence the current
where B is the flux density (Tesla). In
switching power supplies, almost all magnetic
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reduced, so the resistance at high frequency
(and resulting losses) can be many times
gJ:eater than at low freQuencv.
Fig. 1 -IsQ/ated CQnductQrat LQW Frequency
distributes itself uniformly throughout the wire
so as to minimize the resistance loss and the
total energy expended.
Around any closed path outside the wire
(and inside the return current), magneto-motive
force F is constant and equal to total current I.
But field intensity H varies inversely with the
r,adial distance, because constant F is applied
across an increasing t ( =2m).
Within the conductor, F at any radius must
equal the enclosed current at that radius,
therefore F is proportional to r2.
Fig. 3 -High Frequency Cu"ent Distribution
Penetration depth: Penetration or skin
depth, OPEN, is defmed as the distance from
the surface to where the current density is l/e
times the surface current density (e is the
naturallog base)[l]:
OPEN = [ p/(1TIJ.£)]112 m
where p is resistivity. For copper at 100°C,
p = 2.3.10-6 n-cm, IJ.= IJ.o= 41T.10°7,and:
OPEN = 7.5/(£)112 cm
(6)
Fig. 2 -Eddy Current at High Frequency
At high frequency: Figure 2 is a super-
position model that explains what happens
when the frequency rises. The dash lines repre-
sent the uniform low frequency current distri-
bution, as seen in Fig. I. When this current
changes rapidly, as it will at high frequency, the
flux within the wire must also change rapidly.
The changing flux induces a voltage loop, or
eddy, as shown by the solid lines near the wire
surface. Since this induced voltage is within a
conductor, it causes an eddy current coincident
with the voltage. Note how this eddy current
reinforces the main current flow at the surface,
but opposes it toward the center of the wire.
The result is that as frequency rises, current
density increases at the conductor surface and
decreases toward zero at the center. as shown
in Fig. 3. The current tails off exponentially
within the conductor. The portion of the
conductor that is actually carrying current is
From (6), OPEN= .024 cm at 100 kHz, or
.0075 cm at 1 MHz.
Eqs. (5) and (6) are accurate for a flat con-
ductor surface, or when the radius of curvature
is much greater than the penetration depth.
Although the current density tails off expo-
nentially from the surface, the high frequency
resistance (and loss) is the same as if the cur-
rent density were constant from the surface to
the penetration depth, then went abruptly to
zero as shown on the right hand side of Fig. 3.
This equivalent rectangular distribution is
easier to apply.
Equivalent circuit model: Another way of
looking at the high frequency effects in trans-
former windings and circuit wiring is through
the use of an equivalent electrical circuit
model. This approach is probably easier for a
circuit designer to relate to.
Figure 4 is the equivalent circuit of the
isolated conductor of Figs. 1 to 3. With current
I flowin, through the wire, L% accounts for the
energy ~L%I2 stored in the external magnetic
field. L% is the inductance of the wire at high
frequencies.
Point A represents the outer surface of the
conductor, while B is at the center. R; is the
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(5)
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Fig. 4 -Conductor Equivalent Circuit
resistance, distributed through the wire from
surface to center. Think of the wire as divided
into many concentric cylinders of equal cross
section area. The Ri elements shown in the
drawing would correspond to the equal resis-
tance of each of the cylinders. Likewise, the
internal inductance L; accounts for the magnet-
ic energy distributed through the cylindrical
sections. The energy stored in each section
depends on the cumulative current flowing
through the elements to the right of that
section in the equivalent circuit.
Note that external inductance Lx of the wire
(or the leakage inductance of a winding) limits
the maximum di/dt through the wire, depend-
ing on the source compliance voltage, no
matter haw fast the switch turns on.
The time domain: If a rapidly rising current
is applied to the wire, the voltage across the
wire is quite large, mostly across Lx. Internal
inductance Li blocks the current from the wire
interior, forcing it to flow at the surface
through the left-most resistance element, even
after the current has reached its final value and
the voltage across Lx collapses. Although the
energy demand of Lx is satisfied, the voltage
across the wire is still quite large because
current has not penetrated significantly into the
wire and must flow through the high resistance
of the limited cross-section area at the surface.
Additional source energy is then mostly dissi-
pated in the resistance of this surface layer.
The voltage across this Ri element at the
surface is impressed across the adjacent Li ele-
ments toward the center of the wire, causing
the current in L; near the surface to rise.
Current cannot penetrate without a field being
generated within the conductor, and this
requires energy. As time goes on, conduction
propagates from the surface toward the center
(at B in the equivalent circuit), storing energy
in L;. More of the resistive elements conduct,
lowering the total resistance and reducing the
energy going into losses. Finally, conduction is
uniform throughout the wire, no further energy
goes into the magnetic fields external or
internal to the wire, and a small amount of
energy continues to be dissipated in Ri over
time.
Note that the concept of skin depth has no
meaning in the time domain.
The frequency domain: Referring again to
Fig. 4 with a sine wave current applied to the
terminals, it is apparent that at low frequencies,
the reactance of internal inductance Li is neg-
ligible compared to Ri. Current flow is uniform
throughout the wire and resistance is minimum.
But at high frequency, current flow will be
greatest at the surface (A), tailing off exponen-
tially toward the center (B).
Penetration depth (skin depth) is clearly
relevant in the frequency domain. At any
frequency, the penetration depth from Eq. (5)
or (6) reveals the percentage of the wire area
that is effectively conducting, and thus the ratio
of dc resistance to ac resistance at that
frequency.
Although the current waveforms encountered
in most switching power supplies are not
sinusoidal, most papers dealing with the design
of high frequency transformer windings use a
sinusoidal approach based on work done by
Dowell in 1966.[2] Some authors use Fourier
analysis to extend the sinusoidal method to
non-sinusoidal waveforms.
Proximity Effect
Up to this point a single isolated conductor
has been considered. Its magnetic field extends
radially in all directions, and conduction occurs
across the entire surface.
When another conductor is brought into
close proximity to the first, their fields add
vectorially. Field intensity is no longer uniform
around the conductor surfaces, so high frequen-
cy current flow will not be uniform.
For example, if the round wire of Fig. 1 is
close to another wire carrying an equal current
in the opposite direction (the return current
path?), the fields will be additive between the
two wires and oppose and cancel on the out-
sides. As a result, high frequency current flow
is concentrated on the wire surfaces facing each
other, where the field intensity is greatest, with
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little or no current on the outside surfaces
where the field is low. This pattern arranges
itself so as to minimize the energy utilized,
hence inductance is minimized. As the wires
are brought closer together, cancellation is
more complete. The concentrated field volume
decreases, so the inductance is reduced.
Circuit wiring: The field and current distri-
bution with round wires is not easy to compute.
A sinlpler and more practical example is given
in Figure 5. The two flat parallel strips shown
are actually the best way to implement high
frequency wiring, minimizing the wiring induc-
tance and eddy current losses. These strips
could be two wide traces on opposite sides of
a printed circuit board. (Don't use point-to-
point wiring. It is much more important to
collapse the loop and keep the outgoing and
return conductors as intimate as possible, even
if the wiring distances are greater .)
length, divided equally between each of the two
conductors. If one conductor is much wider
than the other, such as a strip vs. a ground
plane, most of the inductance calculated in (6)
is in series with the narrower conductor. This
is good for keeping down noise in the ground
returns.
Note that current penetration is from one side
only --the side where the field is. This means
that a strip thicker than the penetration depth
is not fully utilized. The equivalent circuit
model of Fig. 4 still applies, with A at the
surface adjacent to the field. But B becomes
the opposite side of the strip, not the center,
since there is no penetration from the side with
no field.
Bad practice: Figures 6 and 7 show what not
to do for circuit wiring (unless you want high
inductance and eddy current losses). Although
these strips have large surface areas, proximity
effects in these configurations result in very
little surface actually utilized. Remember that
the field is concentrated directly between the
two conductors so as to minimize the stored
energy.
In Fig. 6 this results in current flow only at
the edges facing each other. Also, because the
concentrated field region is short, the energy
density is very high, and the inductance is
several times greater than in Fig. 5.
The Fig. 7 configuration is not quite as bad
as Fig. 6 because the current does spread out
somewhat in one of the two conductors, but it
is still many times worse than the proper con-
figuration in Fig. 5. The message is: large
I---t--"i
1+ + + + +11-
1.
iT
Fig. 5 -Circuit Wiring -Flat Parallel Strip
The + signs indicate current flow into the
upper strip, the. indicates current out of the
lower strip. Between the strips, the magnetic
field is high and uniform, so the current is
spread out uniformly on the inner surfaces. On
the outside of the strips the field is very low, so
the current is almost zero. This results in the
minimum possible energy storage (and wiring
inductance) for this configuration. If the
breadth of the strip, t, is much greater than
the separation, w, the energy is almost entirely
contained between the two strips. Then t and
ware the length and width of the field, and can
be used to calculate the inductance. Convertin~
Eq. (4) to cm and with N = 1 turn, the induc-
tance per centimeter length of the 2-conductor
strip is:
1
!1 11
1
Fig. 6 -Bad Wiring Practice -Side by Side
L = 12.5 wit
oHlcm
(7)
[~
If the strips have a breadth of 1 cm and are
separated by 0.1 cm, the combined inductance
of the pair is only 1.25 oH for each centimeter
Fig. 7 -Bad Wiring Practice -Right Angled
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surface area doesn't improve high frequency
performance if the configuration is wrong.
Inductor Windings: Figure 8 is a simple
inductor. The winding consists of 4 turns in a
single layer. Assuming a current of 1 Ampere
through the winding, the total magneto-motive
force F = NI along any path linking the 4 turns
is 4 Ampere-turns. The field is quite linear
across the length of the window because of the
addition of the fields from the individual wires
in this linear array. The winding could have
been a flat strip carrying 4 Amps with the same
result.
I~
-
Fig. 9 -Transfonner Windings
is neglected). So if the secondary load current
is 4 A through 1 turn, the primary current
through 4 turns must be 1 Amp. The fields
tend to cancel not only outside both windings,
but in the center of the two windings as well.
Whatever field might remain is shorted out by
the high permeability core which has no gap.
Thus the field generated by the current in the
windings, F = 4 A, exists only between the
windings: So at high frequency, current flow is
on the outside of the inner winding and on the
inside of the outer winding, adjacent to the
field.
Fig. 8 -Inductor Winding
Multiple Layer Windings
Figure 10 shows a transformer with multi-
layer windings and its associated low frequency
mmf (F) and energy density diagrams. One half
of the core and windings are depicted. At low
frequency, current (not shown) is uniformly
distributed through all conductors, because they
are much thinner than the penetration depth.
Without the ferrite core, the field outside of
the winding would have been weak because of
cancellation, but with the high permeability
core, the external field is completely shorted
out. This means the entire field, F = NI is
contained across the window inside the wind-
ing. Field intensity, H equals NI/t. In the
center, the entire field is compressed across the
small air gap. Field intensity (H, = NI/t.) is
therefore much greater within the gap, so the
energy stored in the gap (using Eq. 2 or 3) is
much greater than the energy in the much larg-
er window.
At high frequency, current flow is concentra-
ted on the inner surface of the coil, adjacent to
the magnetic field. The field outside the coil is
negligible, so no current flows on the outer
surface.
Transformer Windings: Figure 9 shows a
transformer with a four turn single layer
primary and a 1 turn single layer copper strip
secondary. In any transformer, the sum of the
Ampere-turns in all windings must equal zero
(except for a small magnetizing current which
F"=Ni~L
JL~L
Fig. 10- Mu/tip/e Layer Winding
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