P27_028.PDF

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Chapter 27 - 27.28
28. We use R
L/A . The diameter of a 22-gauge wire is 1 / 4 that of a 10-gauge wire. Thus from R = ρL/A
we find the resistance of 25ft of 22-gauge copper wire to be R =(1 . 00Ω)(25ft / 1000ft)(4) 2 =0 . 40Ω .
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