P16_009.PDF
(
65 KB
)
Pobierz
Chapter 16 - 16.9
9. (a) The amplitude is half the range of the displacement, or
x
m
=1
.
0mm.
(b) The maximum speed
v
m
is related to the amplitude
x
m
by
v
m
=
ωx
m
,where
ω
is the angular
frequency. Since
ω
=2
πf
,where
f
is the frequency,
v
m
=2
πfx
m
=2
π
(120Hz)
1
.
0
10
−
3
m
=0
.
75 m
/
s
.
(c) The maximum acceleration is
a
m
=
ω
2
x
m
=(2
πf
)
2
x
m
=(2
π
(120Hz))
2
1
.
0
×
10
−
3
m
= 570 m
/
s
2
.
×
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Inne pliki z tego folderu:
P16_096.PDF
(64 KB)
P16_006.PDF
(64 KB)
P16_013.PDF
(58 KB)
P16_009.PDF
(65 KB)
P16_002.PDF
(60 KB)
Inne foldery tego chomika:
chap01
chap02
chap03
chap04
chap05
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