kolbrek2884 Horn Theory Part 1.pdf

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Tube, Solid State,
Loudspeaker Technology
Article prepared for www.audioXpress.com
Horn Theory: An Introduction, Part 1
By Bjørn Kolbrek
This author presents a two-part introduction to horns—their definition,
features, types, and functions.
tical horns, as it applies to loudspeakers.
It reviews the basic assumptions behind
classical horn theory as it stands, presents
the different types of horns, and discusses their
properties. Directivity control, wave-front shapes,
and distortion are also discussed.
In this article, I try to keep the math
simple, and, where it is required, I explain
or illustrate the meaning of the equations.
The focus is on understanding what is
going on in a horn. The practical aspects
of horn design are not treated here.
ρ 0 : Density of air, 1.205 kg/m 3 .
f : Frequency, Hz.
ω: Angular frequency, radians/s, ω = 2πf.
k : Wave number or spatial frequency,
there will be a considerable mismatch
between the source and the load. The
result is that most of the energy put into
a direct radiating loudspeaker will not
reach the air, but will be converted to
heat in the voice coil and mechanical
resistances in the unit. The problem is
worse at low frequencies, where the size
of the source will be small compared to
a wavelength and the source will merely
push the medium away. At higher fre-
quencies, the radiation from the source
will be in the form of plane waves that
do not spread out. The load, as seen from
the driver, is at its highest, and the system
is as efficient as it can be.
If you could make the driver radiate
plane waves in its entire operating range,
efficient operation would be secured at all
frequencies. The driver would work into
a constant load, and if this load could be
made to match the impedances of the
driver, resonances would be suppressed.
This is because the driver is a mechani-
cal filter, which needs to be terminated
in its characteristic impedance, ideally a
pure resistance. If the driver is allowed
to radiate plane waves, resistive loading
is secured.
The easiest way to make the driver
radiate plane waves is to connect it to a
long, uniform tube. But the end of the
tube will still be small compared to a
wavelength at low frequencies. To avoid
reflections, the cross section of the tube
must be large compared to a wavelength,
but, at the same time, it must also be
radians/m, k = 2 f
c c
ω π
=
.
S : Area.
p : Pressure.
Z A : Acoustical impedance.
j : Imaginary operator, j = √-1.
THE PURPOSE OF A HORN
It can be useful to look at the purpose
of the horn before looking at the theory.
Where are horns used, and for what?
Throughout the history of electroa-
coustics, there have been two important
aspects:
Loading of the driver
Directivity control
You would also think that increasing the
output would be one aspect of horns, but
this is included in both. Increasing the
loading of the driver over that of free air
increases efficiency and hence the out-
put, and concentrating the sound into a
certain solid angle increases the output
further.
Loading of the Driver . The loudspeaker,
which is a generator of pressure, has an
internal source impedance and drives an
external load impedance. The air is the
ultimate load, and the impedance of air is
low, because of its low density.
The source impedance of any loud-
s p eaker, on the other hand, is high, so
TERMINOLOGY
The article includes the following termi-
nology:
Impedance : Quantity impeding or re-
ducing flow of energy. Can be electrical,
mechanical, or acoustical.
Acoustical Impedance : The ratio of
sound pressure to volume velocity of air.
In a horn, the acoustical impedance will
increase when the cross-section of the
horn decreases, as a decrease in cross sec-
tion will limit the flow of air at a certain
pressure.
Volume Velocity : Flow of air through a
surface in m 3 /s, equals particle velocity
times area.
Throat : The small end of the horn,
where the driver is attached.
Mouth : The far end of the horn, which
radiates into the air.
Driver : Loudspeaker unit used for driv-
ing the horn.
c : The speed of sound, 344m/s at 20° C.
audioXpress 2008 1
T his article deals with the theory of acous-
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small to fit the driver and present the
required load. To solve this dilemma, you
need to taper the tube.
When you do this, you can take radia-
tion from the driver in the form of plane
waves and transform the high pressure,
low velocity vibrations at the throat into
low pressure, high velocity vibrations that
can efficiently be radiated into the air.
Depending on how the tube flares, it is
possible to present a load to the driver that
is constant over a large frequency range.
Directivity Control . The directivity of
a cone or dome diaphragm is largely un-
controlled, dictated by the dimensions
of the diaphragm, and heavily depen-
dent on f requency, becoming sharper
and sharper as frequency increases. You
can solve this problem by using multiple
driving units and digital signal process-
ing, but a far simpler and cheaper way to
achieve predictable directivity control is
to use a horn. The walls of the horn will
restrict the spreading of the sound waves,
so that sound can be focused into the
areas where it is needed, and kept out of
areas where it is not.
Directivity control is most important
in sound reinforcement systems, where a
large audience should have the same dis-
tribution of low and high frequencies, and
where reverberation and reflections can be
a problem. In a studio or home environ-
ment, this is not as big a problem.
As the art and science of electroacous-
tics has developed, the focus has changed
from loading to directivity control. Most
modern horns offer directivity control at
the expense of driver loading, often pre-
senting the driver with a load full of reso-
nances and reflections. Figure 1 compares
the throat impedance of a typical constant
directivity horn (dashed line) with the
throat impedance of a tractrix horn (solid
line) 1 . The irregularities above 8kHz come
from higher order modes.
Initially, it is a three-dimensional prob-
lem, but solving the wave equation in 3D
is very complicated in all but the most
elementary cases. The wave equation for
three dimensions (in Cartesian coordi-
nates) looks like this 2
2
2
2
2 2
is insignificant.
2. The medium is considered to be a
uniform fluid. This is not the case with
air, but is permissible at the levels (see
1) and frequencies involved.
3. Viscosity and friction are neglected.
The equations involving these quanti-
ties are not easily solved in the case of
horns.
4. No external forces, such as gravity, act
on the medium.
5. The motion is assumed irrotational.
6. The walls of the horn are perfectly
rigid and smooth.
7. The pressure is uniform over the
wave-front. Webster originally consid-
ered tubes of infinitesimal cross-section,
and in this case propagation is by plane
waves. The horn equation does not re-
quire plane waves, as is often assumed.
But it requires the wave-front to be a
function of x alone. This, in turn, means
that the center of curvature of the wave-
fronts must not change. If this is the
case, the horn is said to admit one-pa-
rameter (1P) waves 6 , and according to
Putland 7 , the only horns that admit 1P
waves are the uniform tube, the para-
bolic horn with cylindrical wave-fronts,
and the conical horn. For other horns,
you need the horn radius to be small
compared to the wavelength.
c
0
(1)
2
2
2 2
∂ ∂ ∂ ∂
x y z
This equation describes how sound waves
of very small (infinitesimal) amplitudes
behave in a three-dimensional medium.
I will not discuss this equation, but only
note that it is not easily solved in the case
of horns.
In 1919, Webster 3 presented a solu-
tion to the problem by simplifying equa-
tion 1 from a three-dimensional to a
one-dimensional problem. He did this
by assuming that the sound energy was
uniformly distributed over a plane wave-
front perpendicular to the horn axis, and
considering only motion in the axial di-
rection. The result of these simplications
is the so-called “Webster’s Horn Equa-
tion,” which can be solved for a large
number of cases:
2
φ + −φ=
k 0
(2)
dx dx dx
π , the wave number or spatial fre-
quency (radians per meter),
φ is the velocity potential (see appendix
for explanation), and S is the cross-sec-
tional area of the horn as a function of x.
c
Because the horn equation is not able to
predict the interior and exterior sound
field for horns other than true 1P horns,
it has been much criticized. It has, how-
ever, been shown 8, 9 that the approxima-
tion is not as bad as you might think in
the first instance. Holland 10 has shown
that you can predict the performance of
horns of arbitrary shape by considering
the wave-front area expansion instead of
the physical cross-section of the horn. I
have also developed software based on
the same principles, and have been able
to predict the throat impedance of horns
with good accuracy.
The derivation of equation 2 is given
in the appendix. You can use this equa-
tion to predict what is going on inside
a horn, neglecting higher order effects,
but it can’t say anything about what is
going on outside the horn, so it can’t
predict directivity. Here are the assump-
tions equation 2 is based on 4,5 :
1. Infinitesimal amplitude: The sound
pressure amplitude is insignificant com-
pared to the steady air pressure. This
condition is easily satisfied for most
speech and music, but in high power
sound reinforcement, the sound pres-
sure at the throat of a horn can eas-
ily reach 150-170dB SPL. This article
takes a closer look at distortion in horns
due to the nonlinearity of air later, but
for now it is sufficient to note that the
distortion at home reproduction levels
FUNDAMENTAL THEORY
Horn theory, as it has been developed,
is based on a series of assumptions and
simplifications, but the resulting equa-
tions can still give useful information
about the behavior. I will review the as-
sumptions later, and discuss how well
they hold up in practice.
The problem of sound propagation in
horns is a complicated one, and has not
yet been rigorously solved analytically.
SOLUTIONS
This section presents the solution of
equation 2 for the most interesting horns,
and looks at the values for throat imped-
ance for the different types. You can cal-
culate this by solving the horn equation,
but this will not be done in full math-
ematical rigor in this article.
The solution of equation 2 can, in a
2 audioXpress 2008
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 
∂φ ∂φ∂φ∂φ
− + + =
t
d d lnS d
2
where
k = 2 f
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general way, be set up as a sum of two
functions u and v:
φ = Au + Bv (3)
where A and B represent the outgoing
(diverging) and reflected (converging)
wave, respectively, and u and v depend on
the specific type of horn.
In the case of an infinite horn, there is
no reflected wave, and B = 0. This article
first considers infinite horns, and pres-
ents the solutions for the most common
types 11 . The solutions are given in terms
of absolute acoustical impedance,
c
spherical coordinates. If you use spheri-
cal coordinates, the cross-sectional area
of the spherical wave-front in an axi-
symmetric conical horn is S = Ω(x+x 0 ) 2 ,
where x 0 is the distance from the vertex
to the throat, and Ω is the solid angle of
the cone. If you know the half angle θ
(wall tangent angle) of the cone,
Ω = 2π(1 - cosθ). (5)
In the case where you are interested in
calculating the plane cross-sectional area
at a distance x from the throat,
satisfying performance at low frequen-
cies. As such, the conical expansion is
not very useful in bass horns. Indeed,
the conical horn is not very useful at all
in applications requiring good loading
performance, but it has certain virtues in
directivity control.
EXPONENTIAL HORN
Imagine you have two pipes of unequal
cross-sectional areas S 0 and S 2 , joined by
a third segment of cross-sectional area
S 1 , as in Fig. 3 . At each of the disconti-
nuities, there will be reflections, and the
total reflection of a wave passing from S 0
to S 2 will depend on S 1 . It can be shown
that the condition for least reflection oc-
curs when
S 1 = √S 0 S 2 . (8)
This means that S 1 = S 0 k and S 2 = S 1 k,
thus S 2 = S 0 k 2 . Further expansion
along this line gives for the nth
segment, S n = S 0 k n , given that each
segment has the same length. If k
= e m , and n is replaced by x, you
have the exponential horn, where
the cross-sectional area of the
wave-fronts is given as S = S t e mx .
If you assume plane wave-fronts,
this is also the cross-sectional area
of the horn at a distance x from
the throat.
The exponential horn is not a
true 1P-horn, so you cannot ex-
actly predict its performance. But
much information can be gained
from the equations.
The throat impedance of an in-
finite exponential horn is
c
+
=  
x x
2
.
( )
0
ρ
o
t
;
S xS
t
(6)
x0
S
you can find the specific throat imped-
ance (impedance per unit area) by mul-
tiplying by S t , the throat area, and the
normalized throat resistance by multiply-
ing by
The throat impedance of an infinite con-
ical horn is
c 2 2
 
ρ +
=  
+ 
o
k x jkx
0
0
.
z
A
(7)
S 1kx
2 2
t
0
S
ρ
.
t
c
o
THE PIPE AND THE
PARABOLIC HORN
Both these horns are true 1P
horns. The infinite pipe of uni-
form cross-section acts as a pure
resistance equal to
c
ρ
o
z
=
A
S
t
(4)
An infinite, uniform pipe does not
sound very useful. But a suitably
damped, long pipe (plane wave
tube) closely approximates the re-
sistive load impedance of an in-
finite pipe across a wide band of
frequencies, and is very valuable
for testing compression drivers 12,
13 . It presents a constant frequency
independent load, and as such acts like
the perfect horn.
The parabolic horn is a true 1P horn
if it is rectangular with two parallel sides,
the two other sides expanding linearly,
and the wave-fronts are concentric cylin-
ders. It has an area expansion given as
S = S t x. The expression for throat im-
pedance is very complicated, and will not
be given here.
The throat impedances for both the
uniform pipe and the parabolic horn are
given in Fig. 2 . Note that the pipe has the
best, and the parabolic horn the worst,
loading performance of all horns shown.
FIGURE 2: Throat acoustical resistance r A and reac-
tance x A as a function of frequency for different horn
types.
ρ
m m
2
o
You should note that equation 7 is iden-
tical to the expression for the radiation
impedance of a pulsating sphere of radius
x 0 .
z
= − +
1
j
(9)
A
2
S
2k
4k
t
, the throat
resistance becomes zero, and the horn
is said to cut off. Below this frequency,
The throat resistance of the conical
horn rises slowly ( Fig. 2 ). At what fre-
quency it reaches its asymptotic value de-
pends on the solid angle Ω, being lower
for smaller solid angle. This means that
for good loading at low frequencies, the
horn must open up slowly.
As you will see later, a certain mini-
mum mouth area is required to mini-
mize reflections at the open end. This
area is larger for horns intended for low
frequency use (it depends on the wave-
length), which means that a conical horn
would need to be very long to provide
CONICAL HORN
The conical horn is a true 1P horn in
FIGURE 3: Joined pipe segments.
audioXpress 2008 3
When m = 2k or f = mc
4 π
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the throat impedance is entirely reactive
and is
Above cutoff, the throat impedance of
an infinite hyperbolic horn is
ance is purely reactive. But what happens
at this frequency? What separates the ex-
ponential and hyperbolic horns from the
conical horn that does not have a cutoff
frequency?
To understand this, you first must
look at the difference between plane and
spherical waves 10 . A plane wave propa-
gating in a uniform tube will not have
any expansion of the wave-front. The
normalized acoustical impedance is uni-
form and equal to unity through the en-
tire tube.
A propagating spherical wave, on the
other hand, has an acoustical impedance
that changes with frequency and distance
f rom the source. At low f requencies
and small radii, the acoustical imped-
ance is dominated by reactance. When
kr = 1—i.e., when the distance from the
source is
ρ
c
m m
2
.
1
o
z j
= − −
1
(10)
1
T
A
2
S 2k 4k
2
c
t
ρ
µ
µ
o
, (12)
z
j
=
+
A
2
2
S
t
1 T
− −
1 T
The throat impedance of an exponential
horn is shown in Fig. 2 . Above the cut-
off frequency, the throat resistance rises
quickly, and the horn starts to load the
driver at a much lower frequency than
the corresponding conical horn. In the
case shown, the exponential horn throat
resistance reaches 80% of its final value
at 270Hz, while the conical horn reaches
the same value at about 1200Hz.
An infinite horn will not transmit
anything below cutoff, but it’s a different
matter with a finite horn, as you will see
later.
You should note that for an exponen-
tial horn to be a real exponential horn,
the wave-front areas, not the cross-sec-
tional areas, should increase exponential-
ly. Because the wave-fronts are curved,
as will be shown later, the physical horn
contour must be corrected to account for
this.
1
− −
1
2
2
µ µ
and below cutoff, the throat impedance is
entirely reactive and is
 
 
µ µ
1 1
1
c
2
(13)
ρ
o
z j
=
A
 
 
2
S
t
1 T
 
1
2
 
where
µ is the normalized frequency, µ=
f
f
c
.
The throat impedance of a hypex horn
with T = 0.5 is shown in Fig. 2 . The
throat impedance of a family of horns
with T ranging from 0 to 5 is shown in
Fig. 5 .
Exponential and hyperbolic horns have
much slower flare close to the throat than
the conical horn, and thus have much
better low frequency loading. When T <
1, the throat resistance of the hyperbolic
horn rises faster to its asymptotic value
than the exponential, and for T < √2 it
rises above this value right above cutoff.
The range 0.5 < T < 1 is most useful
when the purpose is to improve loading.
When T = 0, there
is no reactance com-
ponent above cutoff
for an infinite horn,
but the large peak in
the throat resistance
may cause peaks in
the SPL response of
a horn speaker.
Due to the slower
flaring close to the
throat, horns with
low values of T will
also have some-
what higher distor-
tion than horns with
higher T values.
—the reactive and resistive
parts of the impedance are equal, and
above this frequency, resistance domi-
nates.
The difference between the two cases
is that the air particles in the spherical
wave move apart as the wave propa-
gates; the wave-front becomes stretched.
This introduces reactance into the sys-
tem, because you have two components
in the propagating wave: the pressure
that propagates outward, and the pres-
HYPERBOLIC HORNS
The hyperbolic horns, also called hyper-
bolic-exponential or hypex horns, were
first presented by Salmon 14 , and is a gen-
eral family of horns given by the wave-
front area expansion
2
x
x
.
S S cosh Tsinh
x
t
(11)
T is a parameter that sets the shape of
the horn ( Fig. 4 ). For T = 1, the horn is
an exponential horn, and for T → ∝ the
horn becomes a conical horn.
x 0 is the reference distance given as x o =
0
x
0
c
2 π where f c is the cutoff frequency.
A representative selection of hypex con-
tours is shown in Fig. 4 .
c
FIGURE 4: A family of representative
hypex contours, T = 0 (lower curve), 0.5,
1, 2, 5, and infinite (upper curve).
WHAT IS CUTOFF?
Both exponential
and hyperbolic horns
have a property called
cutoff. Below this
frequency, the horn
transmits nothing,
and its throat imped-
FIGURE 5: Throat impedance of a family of hypex horns.
4 audioXpress 2008
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λ
π
2
= +
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sure that stretches the wave-front. The
propagating pressure is the same as in
the non-expanding plane wave, and gives
the resistive component of the imped-
ance. The stretching pressure
steals energy from the propagat-
ing wave and stores it, introduc-
ing a reactive component where
no power is dissipated. You can
say that below kr = 1, there is re-
actively dominated propagation,
and above kr = 1 there is resistive
dominated propagation.
If you apply this concept to the
conical and exponential horns by
looking at how the wave-fronts
expand in these two horns, you
will see why the cutoff phenom-
enon occurs in the exponential
horn. You must consider the flare
rate of the horn, which is defined
as (rate of change of wave-front
area with distance)/(wave-front
area).
In a conical horn, the flare rate
changes throughout the horn,
and the point where propagation
changes from reactive to resistive
changes with frequency through-
out the horn.
In an exponential horn, the
flare rate is constant. Here the
transition from reactive to resis-
tive wave propagation happens at
the same frequency throughout
the entire horn. This is the cutoff
frequency. There is no gradual
transition, no frequency depen-
dent change in propagation type,
and that’s why the change is so
abrupt.
= (16)
where Z m is the terminating impedance
at the mouth.
gZ b
The expressions for a, b, f, and g are
quite complicated, and are given by
Stewart 15 for the uniform tube, the coni-
cal, and the exponential horn.
You see that the value of mouth
impedance will dictate the value
of the throat impedance. As ex-
plained previously, there will usu-
ally be reflections at the mouth,
and depending on the phase and
magnitude of the reflected wave,
it may increase or decrease the
throat impedance. A horn with
strong reflections will have large
variations in throat impedance.
Reflections also imply stand-
ing waves and resonance. To avoid
this, it is important to terminate
the horn correctly, so that reflec-
tions are minimized. This will be
discussed in the next section.
It’s interesting to see what ef-
fect the length has on the perfor-
mance of a horn. Figure 6 shows
the throat impedance of 75Hz
exponential horns of different
lengths, but the same mouth size.
As the horn length increases, the
throat resistance rises faster to a
useful value, and the peaks in the
throat impedance become more
closely spaced.
Finite horns will transmit
sound below their cutoff fre-
quency. This can be explained as
follows: the horn is an acousti-
cal transformer, transforming the
high impedance at the throat to
a low impedance at the mouth.
But this applies only above cutoff.
Below cutoff there is no trans-
former action, and the horn only
adds a mass reactance.
An infinite exponential horn
can be viewed as a finite exponen-
tial horn terminated by an infinite
one with the same cutoff. As you
have seen, the throat resistance
of an infinite exponential horn is
zero below cutoff, and the throat
resistance of the finite horn will
thus be zero. But if the imped-
ance present at the mouth has a
non-zero resistance below cutoff,
a resistance will be present at the
throat. This is illustrated in Fig. 7 ,
where a small exponential horn
with a mouth three times larger
t
a fZ
m
FIGURE 6: The effect of increasing the length of a 75Hz
exponential horn with krm = 0.5. The lengths are (top to
bottom) 50, 100, and 200cm.
FINITE HORNS
For a finite horn, you must con-
sider both parts of equation 3.
By solving the horn equation this
way 3, 15 , you get the following
results for pressure and volume
velocity at the ends of a horn:
p m = ap t + bU t (14)
U m = fp t + gU t (15)
where p and U denote the pres-
sure and volume velocity, respec-
tively, and the subscripts denote
the throat and mouth of the horn.
You can now find the impedance
at the throat of a horn, given that
you know a, b, f, and g:
FIGURE 7: Finite exponential horn terminated by an
infinite pipe.
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m
Z
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