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Chapter 19 - 19.76

76. Consider the object of mass m 1 falling through a distance h . The loss of its mechanical energy is

∆ E = m 1 gh. This amount of energy is then used to heat up the temperature of water of mass m 2 :

∆ E = m 1 gh = Q = m 2 c ∆ T . Thus, the maximum possible rise in water temperature is

∆ T =

m 1 gh

m 2 c

(6 . 00 kg) 9 . 8m / s 2 (50 . 0m)

(0 . 600 kg) 4190 J / kg

C ◦

=1 . 17 C ◦ .