p42_043.pdf
(
58 KB
)
Pobierz
Chapter 42 - 42.43
43. (a) The probability that a state with energy
E
is occupied is given by
P
(
E
)=
1
e
(
E
−
E
F
)
/kT
+1
where
E
F
is the Fermi energy,
T
is the temperature on the Kelvin scale, and
k
is the Boltz-
mann constant. If energies are measured from the top of the valence band, then the energy
associated with a state at the bottom of the conduction band is
E
=1
.
11eV. Furthermore,
kT
=(8
.
62
10
−
5
eV
/
K)(300K) = 0
.
02586eV. Forpuresilicon,
E
F
=0
.
555eVand(
E
−
E
F
)
/kT
=
(0
.
555eV)
/
(0
.
02586eV) = 21
.
46. Thus,
P
(
E
)=
1
e
21
.
46
+1
=4
.
79
×
10
−
10
.
For the doped semiconductor, (
E
−
E
F
)
/kT
=(0
.
11eV)
/
(0
.
02586eV) = 4
.
254 and
P
(
E
)=
1
e
4
.
254
+1
=1
.
40
×
10
−
2
.
(b) The energy of the donor state, relative to the top of the valence band, is 1
.
11eV
−
0
.
15eV =
0
.
96eV. The Fermi energy is 1
.
11eV
−
0
.
11eV = 1
.
00eV. Hence, (
E
−
E
F
)
/kT
=(0
.
96eV
−
1
.
00eV)
/
(0
.
02586eV) =
−
1
.
547 and
P
(
E
)=
1
e
−
1
.
547
+1
=0
.
824
.
×
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p42_003.pdf
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chap02
chap03
chap04
chap05
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