P31_087.PDF

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Chapter 31 - 31.87
87. (a) We use U B = 2 Li 2 to solve for the self-inductance:
L = 2 U B
i 2
= 2(25 . 0
×
10 − 3 A) 2 =13 . 9H .
10 − 3 J)
(60 . 0
×
(b) Since U B ∝ i 2 ,for U B to increase by a factor of 4, i must increase by a factor of 2. Therefore, i
should be increased to 2(60 . 0 mA) = 120 mA.
 

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