P18_099.PDF

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Chapter 18 - 18.99
99. (a) The problem asks for the source frequency f . We use Eq. 18-47 with great care (regarding its
±
sign conventions).
f = f 340
−
16
340
−
40
Therefore, with f = 950 Hz, we obtain f = 880 Hz.
(b) We now have
f = f 340 + 16
340 + 40
so that with f = 880 Hz, we find f = 824 Hz.

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