p11_029.pdf

29. Since the belt does not slip, a point on the rim of wheel C has the same tangential acceleration as a

point on the rim of wheel A . This means that α A r A = α C r C ,where α A is the angular acceleration of

wheel A and α C is the angular acceleration of wheel C .Thus,

α C = r A

r C

(1 . 6rad / s 2 )=0 . 64 rad / s 2 .

Since the angular speed of wheel C is given by ω C = α C t , the time for it to reach an angular speed of

ω = 100 rev / min = 10 . 5rad / s starting from rest is

t = ω C

10 . 5rad / s

0 . 64 rad / s 2 =16s .

α A = 10 cm

25 cm

α C =