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variable oscillator
019
C1
R1
10k
T. Giesberts
Although the oscillator in the diagram at first sight resembles a
standard Wien bridge type, it is in fact a variant of it since it is
tuned by varying only one component. This has the advantage of
not needing a carefully selected stereo potentiometer; instead, a
single potentiometer may be used. In the diagram, this is P 1 , and
with values as specified, the output frequency of the oscillator may
be varied between 340 Hz and 3.4 kHz.
The basic Wien bridge consists of R 1 -C 1 and (R 2 +P 1 )-C 2 .
Since in this variant the well-known ×3 attenuation does not occur,
the conditions for stable oscillation are met by including the current
through R 2 +P 1 in the positive feedback loop. This means that the
circuit cannot be based on a single operational amplifier, which is
the reason that IC 1b has been added to it. Diodes D 1 and D 2
ensure reasonable stability of the signal.
The design requires that the resistance of R 4 is more or less
equal to the impedance of network R 5 -R 6 -R 7 P 2 -D 1 -D 2 . Poten-
tiometer P 2 is set to a position which ensures that the level of the
output signal is just below that of the supply voltage: the distortion
is then a minimum. For best results, it may be worthwhile to exper-
iment with the values of R 5 , R 6 , and P 2 .
Frequency control P 1 may have a linear or logarithmic charac-
teristic, although the latter will normally give more linear control.
The frequency, f , is, at least theoretically, determined by
15n
R7
220k
D1
2x
1N4148
R3
10k
R6
150k
D2
R5
10k
P2
P1
R2
1k
2
500
R4
10k
1
6
100k
IC1a
R8
100
3
7
IC1b
5
C2
15n
15V
C5
C3
8
100n
µ
63V
IC1
4
C6
C4
IC1 = TL072
100n
10 µ
63V
15V
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52
Elektor Electronics
7-8/99
10
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f =1/2π
R 1 C 1 √ α,
parallel network D 1 -D 2 by a proper stabilization circuit.
The circuit draws a current of about 4 mA without load. When
a supply voltage of ±15 V is used, the peak output signal is 9.4 V
r.m.s. With the use of a Type TL072 as specified, the circuit can
work from supply voltages as low as ±5 V.
where α=(R 2 +P 1 )/R 1 .
Note the conditions that R 1 =R 3 and C 1 =C 2 .
The circuit has a drawback in that the frequency is dependent
to some degree on the peak value of the signal, which cannot be
nullified with the present design. It can, however, by replacing the
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