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BASIC CIRCUITS
One-Minute Light
Elementary Circuit
by B. Kainka
Loss-free switching, using a Field Effect Transistor (FET) and a capacitor‘s
discharge function, is the base theme of this elementary circuit.
S1
La1
The one-minute light circuit shown
in Figure 1 consists of six compo-
nents, whose functions are easy to
point out. The power source is a 6-
volt battery, paralleled to the branch
point with a lamp and transistor, act-
ing an on/off switch.
Likewise, parallel to the battery
is a node linking a pushbutton
switch coupled to a very high ohmic
valued resistor. The BUZ10 is a Field
Effect Transistor (FET), which differ-
entiates itself from a normal transis-
tor, in so much that almost no base
current is needed for it to switch on
— instead, a voltage at the Gate pin
is required. Thus switching without
performance loss is possible, which
is extremely practical for battery
switching circuits.
The voltage potential between
the pushbutton switch and resistor
determines whether current passes
to the lamp through the switching
transistor or not.
teristics of this transistor in Figure 2
shows, when the Gate/Source-Volt-
age V GS is +6 V, a maximum current
of 12 A flows through the Drain-
Source junction. Strictly speaking,
the diagram is only valid for a Drain-
Source-Voltage of 25 V. Actually, such
a high current does not flow, due to
on the one hand the battery having
an relatively high internal resistance
and on the other hand the sudden
resistance change of the lamp fila-
ment from a low ohmic value in its
cold state to about 60 Ω in a few mil-
liseconds as the filament glows hot.
The current flowing through this
branch is easy determined using
Ohm’s law.
6V
100mA
BT1
T1
D
G
6V
R1
S
C1
BUZ10
100µ
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Figure 1. One –minute light circuit diagram —
there are just of six components.
Typical Transfer Characteristics
I = U / R = 6 V / 60 Ω
= 100 mA
I D =f ( V GS ); V GS = 25V
80
s pulse test, T j = 25 °
C
By the way, the potential loss across
the conducting FET is marginal
thanks to the low drain-source resis-
tance of less than 0.1
24
I D
[A]
20
.
16
Standby mode
Discharging
12
In standby mode the pushbutton is
open. The capacitor is discharged
through the resistor. The transistor
then blocks, allowing no trickle cur-
rent to flow to the lamp.
Pushing on the button, something
else also happens, the capacitor gets
a kick-start charge of +6 V. When
releasing the pushbutton, this poten-
tial remains at the Gate of the
BUZ10, due to the fact that the
capacitor can only discharge itself
very slowly through the high ohmic
value resistor. The voltage across the
capacitor u e decreases not linearly,
but rather in an exponential fashion:
8
4
Switch mode
0
0
2
4
V GS
[V]
6
8
10
One push on the button instanta-
neously brings a potential of +6 V to
the node. This voltage is also seen at
the Gate of the Field Effect Transis-
tor BUZ10. As the Transfer charac-
004107 - 12
Figure 2. The BUZ10 Field Effect Transistor
Transfer characteristics.
u c = U
e -t/RC
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BASIC CIRCUITS
Here, U is the initial capacitor poten-
tial and e the base of natural loga-
rithms, or 2.718. The corresponding
curve (Voltage against Time) is
shown in Figure 3 .
Due to the fact that the capacitor
is slowly discharged, and the BUZ10
conducting sufficiently until the Gate
voltage drops to about 3.75 V, the
lamp glows a short spell after the
pushbutton is released.
The afterglow effect can even be
determined exactly, that is, mathe-
matically. This involves solving the
above formula in the time domain
and using an instantaneous voltage
of u c = 3.75 V:
1.0
0.8
0.625
U C
U
0.6
0.4
0.2
ln ( u c / U )
= –(4,7
10 6
Ω ⋅
100
10 -6 F)
ln (3.75
t [s]
V/6 V)
= –470 s
004107 - 12
ln 0.625
= –470 s ⋅ –0.47
= 221 s
Figure 3. The discharge curve of an ideal capacitor.
not be attained due to the fact that
capacitors (especially electrolytic
ones) also discharge themselves.
This theoretical value will however
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61
t= RC
138909100.002.png
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